j^2+2j-(15)=0

Solution for j^2+2j-(15)=0 equation:

Simplifying
j2 + 2j + -1(15) = 0

Multiply -1 * 15
j2 + 2j + -15 = 0

Reorder the terms:
-15 + 2j + j2 = 0

Solving
-15 + 2j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-5 + -1j)(3 + -1j) = 0

Subproblem 1
Set the factor '(-5 + -1j)' equal to zero and attempt to solve:

Simplifying
-5 + -1j = 0

Solving
-5 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1j = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1j = 0 + 5
-1j = 0 + 5

Combine like terms: 0 + 5 = 5
-1j = 5

Divide each side by '-1'.
j = -5

Simplifying
j = -5
Subproblem 2
Set the factor '(3 + -1j)' equal to zero and attempt to solve:

Simplifying
3 + -1j = 0

Solving
3 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1j = 0 + -3
-1j = 0 + -3

Combine like terms: 0 + -3 = -3
-1j = -3

Divide each side by '-1'.
j = 3

Simplifying
j = 3
Solution
j = {-5, 3}